# Kirchhoff's Laws

Kirchhoff's current law and voltage law, defined by Gustav Kirchhoff, describe the relation of values of currents that flow
through a junction point and voltages in a an electrical circuit loop, in an electrical circuit.

## Kirchhoff's Current Law (KCL)

This is Kirchhoff's first law.

The sum of all currents that enter an electrical circuit junction is 0. The currents enter the junction have positive sign and
the currents that leave the junction have a negative sign:

Another way to look at this law is that the sum of currents that enter a junction is equal to the sum of currents that leave the junction:

#### KCL example

*I*_{1} and *I*_{2} enter the junction

*I*_{3} leave the junction

*I*_{1}=2A, *I*_{2}=3A, *I*_{3}=-1A, *I*_{4}= ?

Solution:

∑*I*_{k} = *I*_{1}*+I*_{2}*+I*_{3}*+I*_{4 }= 0

*I*_{4}* = -I*_{1}* - I*_{2}* - I*_{3 }= -2A - 3A - (-1A) = -4A

Since *I*_{4} is negative, it leaves the junction.

## Kirchhoff's Voltage Law (KVL)

This is Kirchhoff's second law.

The sum of all voltages or potential differences in an electrical circuit loop is 0.

#### KVL example

*V*_{S} = 12V, *V*_{R1} = -4V, *V*_{R2} = -3V

*V*_{R3} = ?

Solution:

∑*V*_{k} = *V*_{S }+* V*_{R1 }+* V*_{R2 }+* V*_{R3
}= 0

*V*_{R3} =* *-*V*_{S }-* V*_{R1}* *-* V*_{R2}
= -12V+4V+3V = -5V

The voltage sign (+/-) is the direction of the potential difference.

## See also